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If a = log(2)3, b = log(2) 5 and c = log...

If `a = log_(2)3, b = log_(2) 5` and `c = log_(7)2`, then `log_(140) 63` in terms of a, b, c is

A

`(2ac+1)/(2c+abc+1)`

B

`(2ac+1)/(2a+c+a)`

C

`(2ac+1)/(2x+ab+a)`

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
D
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