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If int(f(x))/(logsinx)dx=loglogsinx, the...

If `int(f(x))/(logsinx)dx=loglogsinx,` then f(x) is equal to

A

sinx

B

cosx

C

logsinx

D

cotx

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the function \( f(x) \) given the equation: \[ \int \frac{f(x)}{\log(\sin x)} \, dx = \log(\log(\sin x)) \] ### Step 1: Differentiate both sides with respect to \( x \) We start by differentiating both sides of the equation to eliminate the integral. Using the Fundamental Theorem of Calculus, we have: \[ \frac{d}{dx} \left( \int \frac{f(x)}{\log(\sin x)} \, dx \right) = \frac{f(x)}{\log(\sin x)} \] On the right side, we differentiate \( \log(\log(\sin x)) \): \[ \frac{d}{dx} \left( \log(\log(\sin x)) \right) = \frac{1}{\log(\sin x)} \cdot \frac{d}{dx}(\log(\sin x)) \] ### Step 2: Differentiate \( \log(\sin x) \) Now, we need to differentiate \( \log(\sin x) \): \[ \frac{d}{dx}(\log(\sin x)) = \frac{1}{\sin x} \cdot \cos x = \cot x \] ### Step 3: Substitute back into the equation Substituting this back into our equation, we have: \[ \frac{f(x)}{\log(\sin x)} = \frac{\cot x}{\log(\sin x)} \] ### Step 4: Solve for \( f(x) \) Now, we can solve for \( f(x) \) by multiplying both sides by \( \log(\sin x) \): \[ f(x) = \cot x \] ### Final Result Thus, the function \( f(x) \) is: \[ f(x) = \cot x \]
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