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int("In"(x+1)-"In"x)/(x(x+1))dx is equal...

`int("In"(x+1)-"In"x)/(x(x+1))dx` is equal to

A

`-1/2["In"((x+1)/x)]^2+C`

B

`-"In"(x+1)^2-("In"x)^2+C`

C

`-"In"["In"(x+1)/x]+C`

D

`-"In"((x+1)/x)+C`

Text Solution

Verified by Experts

The correct Answer is:
A
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