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intcos2thetalog((costheta+sintheta)/(cos...

`intcos2thetalog((costheta+sintheta)/(costheta-sintheta))d theta` is equal to

A

`(costheta-sintheta)^2log((costheta+sintheta)/(costheta-sintheta))+C`

B

`(costheta+sintheta)^2log((costheta+sintheta)/(costheta-sintheta))+C`

C

`((costheta-sintheta)^2)/2log""((costheta-sintheta)/(costheta+sintheta))+C`

D

`1/2sin2thetalogtan(pi/4+theta)-1/2logsec2theta+C`

Text Solution

Verified by Experts

The correct Answer is:
D
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