Home
Class 12
CHEMISTRY
Number of optical isomers of [Cr(C2O4)3]...

Number of optical isomers of `[Cr(C_2O_4)_3]^(3-)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the number of optical isomers of the complex ion \([Cr(C_2O_4)_3]^{3-}\), we can follow these steps: ### Step 1: Identify the Coordination Number and Geometry The complex \([Cr(C_2O_4)_3]^{3-}\) contains the oxalate ligand \((C_2O_4)^{2-}\), which is a bidentate ligand. Each oxalate ligand can form two bonds with the chromium ion. Since there are three oxalate ligands, the coordination number of chromium in this complex is 6. The geometry of a coordination complex with a coordination number of 6 is typically octahedral. **Hint:** Remember that bidentate ligands attach to the metal at two sites, affecting the overall geometry of the complex. ### Step 2: Determine the Possible Isomers In an octahedral complex with three bidentate ligands, we can have different arrangements of the ligands. The arrangement of the oxalate ligands can lead to different stereoisomers. For the complex \([Cr(C_2O_4)_3]^{3-}\), the possible arrangements can lead to two distinct forms: 1. **Facial (fac) Isomer**: Where three ligands occupy adjacent positions. 2. **Meridional (mer) Isomer**: Where ligands are arranged in a plane. **Hint:** Visualize the arrangement of ligands in the octahedral geometry to identify the fac and mer isomers. ### Step 3: Assess Optical Activity Optical isomers (enantiomers) are non-superimposable mirror images of each other. The fac isomer can exhibit optical activity because it can have a chiral arrangement, leading to two enantiomers (one being the mirror image of the other). On the other hand, the mer isomer does not have a chiral arrangement and thus does not exhibit optical activity. **Hint:** Check for symmetry in the structure; if a molecule has a plane of symmetry, it is not optically active. ### Step 4: Count the Optical Isomers From the analysis: - The fac isomer has 2 optical isomers (enantiomers). - The mer isomer has no optical isomers. Thus, the total number of optical isomers for the complex \([Cr(C_2O_4)_3]^{3-}\) is **2**. ### Final Answer The number of optical isomers of \([Cr(C_2O_4)_3]^{3-}\) is **2**. ---
Promotional Banner

Topper's Solved these Questions

  • JEE MAIN 2021

    JEE MAINS PREVIOUS YEAR|Exercise SECTION-A|100 Videos
  • JEE MAIN 2021

    JEE MAINS PREVIOUS YEAR|Exercise SECTION-B|50 Videos
  • JEE MAIN

    JEE MAINS PREVIOUS YEAR|Exercise CHEMISTRY|150 Videos
  • JEE MAIN 2022

    JEE MAINS PREVIOUS YEAR|Exercise Question|561 Videos

Similar Questions

Explore conceptually related problems

Draw the structures of optical isomers of: (i). [Cr(C_2O_4)_3]^(3-) (ii). [PtCl_2(en)_2]^(2+) (iii). [Cr(NH_3)_2Cl_2(en)]^(o+)

The number of optical isomers possible for [Cr(C_2O_4)_3]^(3-) is

Number of optical isomers possible for

The possible number of the optical isomers in [Cr(en)_(2)CI_(2)]^(o+) is .

If number of geometrical isomers of [Co(NH_3)_3(NO_2)_3] is A and that of [Cr(C_2O_4)_3] is B then find A+B?