A particle travels in a circle of radius 20 cm at a speed thast uniformly increases. If the speed changes from 5.0 m/s to 6.0 m/s in 2.0s, find the angular aceleration.

Explanation

The tangential acceleration is gilven by
` a_t=(dv)/(dt)=(v_2-v_1)/(t_2-t_1)`
`=(6.0-5.0)/2.0m/s^2=0.5m/s^2`
The angula accelerationis `alpha =a_t/r`
`=(0.5m/s^2)/(20 cm)=2.5rads^2`