Find the magnitude of the linear acceleration of a particle moving in a circle of radius 10 cm with uniform speed completing the circle in 4s.

Explanation

The distance covered in completing the circle is `2pir=2pixx10cm.` The linear speed is
`v=2pi r/t`
`=(2pixx10cm)/(4s)=5pi (cm)/s`.
The linear acceleration is
`=v^2/r=((5pi(cm)/s)^2)/(10cm)=2.5pi^2(cm)/s^2`
This acceleration is directed towards the centre of the circle.