The road at a circular turn of radius 10 m is banked by an angle of `10^0`. With what speed should a vehicle move on the turn so that the normal contact force is able to provide the necessary centripetal force?

Explanation

If v is the correct speed
`tantheta=v^2/(rg)
or, `v=sqrt(rg tan theta)`
`=sqrt((10 m)(9.8m/s^2)(tan10^0))=4.2 m/s`.