A car of mass M is moving with a uniform velocity `upsilon` on a horizontal road when the hero of a Hindi film drops himself on it from above. Taking the mass of the hero to be m what will be the velocity of the car after the event?

Explanation

Consier the car plus the hero s the system. IN the horizontla direction, thee is no exterN/Al fore. Since the hero has fallen vertically, so his initial horizontal momentum=0
Initila horizontla momentum of the system =Mv towards right.
FiN/Ally hte heor sticks of to the roof of the car so they move with equal horizontal velocity say V. FiN/Al horizontal momentum of teh system
`=(M+m)V`
`Hence, Mv=(M+m)V`
or, V=(Mv)/M+m`