A space shuttle while travelling at a speed of 4000 km/h with respect to the earth disconnects and ejects a module backward, weighing one sixth of the residual part. If the shuttle ejects the disconnected module at a speed of 100 km/h with respect to the state of the shuttle before the ejection, find the final velocity of the shuttle.

Explanation

Suppose the mass of het shuttle including the module is M. The mass of the module will be M/6. The total linear momentum before disconnection
`=M(4000 km/h)`
The velocity of the ejected module with respect to the earth =it velocilty with respect to the shutle +the velocity of the shuttle with respect to the earth
`=-100km/h+4000km/h=3900km/h`
If the fiN/Al velocity of te shuttle is V then the total fiN/Al liner momentum
`=(5M)/6V+M/6xx3900 km/h`
By the principle of conservation of linear mometum,
`M(4000 km/h)=(5M)/6V+M/6xx3900km/h`
or `V=4020km/h`