Home
Class 11
PHYSICS
A heavy ring fo mass m is clamped on the...

A heavy ring fo mass m is clamped on the periphery of a light circular disc.A small particle having equal mass is clamped at the centre of the disc. The system is rotated in such a way that the centre of mass moves in a circle of radius r with a uniform speed v. We conclude that an external force :

A

`(mv^2)/r` must be acting on the central particle

B

`(2mv^2)/r` must be acting on the central particle

C

`(2mv^2)/r` must be acting on the system

D

`(2mv^2)/r` must be acting on the ring

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • CENTRE OF MASS, LINEAR MOMENTUM, COLLISION

    HC VERMA|Exercise Objective -2|11 Videos
  • CENTRE OF MASS, LINEAR MOMENTUM, COLLISION

    HC VERMA|Exercise Exercises|64 Videos
  • CENTRE OF MASS, LINEAR MOMENTUM, COLLISION

    HC VERMA|Exercise Question For short Answer|25 Videos
  • CALORIMETRY

    HC VERMA|Exercise Exercises|18 Videos
  • CIRCULAR MOTION

    HC VERMA|Exercise Exercises|30 Videos

Similar Questions

Explore conceptually related problems

A particle of mass m is observed from an inertial frame of reference and is found to move in a circle of radius r with a uniform speed v. The centrifugal force on it is

A person applies a constant force vecF on a particle of mass m and finds tht the particle movs in a circle of radius r with a uniform speed v as seen from an inertial frame of reference.

A particle of mass m is circulating on a circle of radius r having angular momentum L then the centripetal force will be

A particle of mass m is being rotated on a vertial circle of radius r. If the speed of particle at the highest point be v, then

A disc of radis R is cut out from a larger disc of radius 2R in such a way that the edge of the hole touches the edge of the disc. Locate the centre of mass of the residual disc.

A metal rign of mass m and radius R is placed on a smooth horizontal table and is set rotating abut its own axis in such a way that each part of the ring moves with a speed v. Find the tension in the ring.

An electric dipole formed by two particles fixed at the ends of a light rod of length l. The mass of each particle is m and the charges are -q and +q . The system is placed in such a way that the dipole axis is parallel to a uniform electric field E that exist in the region. The dipole is slightly rotated abut its centre and released. Show that for small angular displacement, the motion is angular simple harmonic and find its time period.

Read the following paragraph carefully and answer the following: Tie a stone to one end of a string. Take the other end in your hand and rotate the string so that the stone moves along a circle. As long as we are holding the string, we are pulling the stone towards us i.e. towards the centre of the circle and are appliying a force towards it. The force stops acting on it if we release the string. In this case, the stone will fly off along a straight line which is the tangent to the circle at the position of the stone when the string is released, because that the directionn of its velocity at that instant of time. You may recall a similar activity in which a 5 rupee coin kept on a rotating circular disc flies off the disc along the tangent to the disc. Thus, a force acts on any object moving along a circle and it is directed towards the centre of the circle. This is called the Centripetal force. What is centripetal force?

Two small bals A and B, each of mass m, are joined rigidlyl by a light horizontal rol of lengh L. The rod is clasmped at the centre in such a way that it c an rotate freely about a verticl axis through its centre. The systemis rotated with an angualr speed omega about the axis. A particle P of masss m kept at rest sticks to the ball A as the ball collides with it. Find the new angular speed of the rod.

A stone of mass m tied to a string of length l is rotated in a circle with the other end of the string as the centre. The speed of the stone is v. If the string breaks, the stone will move

HC VERMA-CENTRE OF MASS, LINEAR MOMENTUM, COLLISION-Objective -1
  1. Consider the following two equations (A). vecR=1/M sumimivecri and...

    Text Solution

    |

  2. Consider the following two statements: A. linear momentum of the syst...

    Text Solution

    |

  3. Consider the following two statements. (A) Linear momentum of a syst...

    Text Solution

    |

  4. Consider the following two statements: A The linear momentum of a pa...

    Text Solution

    |

  5. All the particles of a body are situated at a distance of X from origi...

    Text Solution

    |

  6. A circular plate of diameter d is kept in contact with a square plate ...

    Text Solution

    |

  7. Consider a system of two identical particles. One is at rest and the o...

    Text Solution

    |

  8. Internal forces can change

    Text Solution

    |

  9. A bullet hits a lock kept at rest on a smooth horizontal surface and g...

    Text Solution

    |

  10. A uniform sphere is place on a smooth horizontal surface and as horizo...

    Text Solution

    |

  11. A body falling vertically downwards under gravity breaks in two parts ...

    Text Solution

    |

  12. A ball kept in a close box moves in the box making collisions with the...

    Text Solution

    |

  13. A body at rest breaks into two pieces of equal masses. The parts will ...

    Text Solution

    |

  14. A heavy ring fo mass m is clamped on the periphery of a light circular...

    Text Solution

    |

  15. The quantities remaining constant in colision are

    Text Solution

    |

  16. A shell is fired from a cannon with a velocity V at an angle theta wit...

    Text Solution

    |

  17. In an elastic collision

    Text Solution

    |

  18. In an inelastic collision

    Text Solution

    |