The resistance of a 0.5 N solution of salt is 20 `Omega` .Calculate the equivalent conductance of the solution if the platinum electrodes are 1.5 cm apart and each having an area of `3.0cm^(2)` .

Explanation

Conductivity, `k= (1)/(rho) = (1)/(R ) ((l)/(A)) = (1)/(20) xx (1.5)/(3.0) = (1)/(40)`
Equivalent conductance, `Lamda_(eq)= (k xx 1000)/(0.5) = (1)/(40) xx (1000)/(0..5) = 50S cm^(2) eq^(-1)`