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A carbon compound contains 12.8% of carb...

A carbon compound contains 12.8% of carbon, 2.1% of hydrogen and 85.1% of bromine. The molecular weight of the compound is 187.9. Calculate the molecular formula of the compound. (Atomic wts: H = 1.008, C = 12.0, Br = 79.9)

A

`CH_(3)Br`

B

`CH_(2)Br_(2)I`

C

`C_(2)H_(4)Br_(2)`

D

`C_(2)H_(4)Br_(3)`

Text Solution

Verified by Experts

The correct Answer is:
C

E.F = `CH_(2)Br`
Wt. of EF `=12 + 2 + 80 = 94`
`n = (M.W)/("wt of EF") = 187.9/94 = 2`
`MF = (EF)_(n) = (CH_(2) Br_(2)) = C_(2)H_(4)Br_(2)`
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