How many carbon atoms are present in 0.35 mole of `C_(6)H_(12)O_(6)`? (Given: `N_(A) = 6.023 xx 10^(23)`)

Options

A. `1.26 xx 10^(2)` carbon atoms
B. `1.26 xx 10^(24)` carbon atoms
C. `1.26 xx 10^(14)` carbon atoms
D. `1.26 xx 10^(48)` carbon atoms

Answer

B

Explanation

`therefore` 1 mole of `C_(6)H_(12)O_(6)` has = 6
0.35 mole of `C_(6)H_(12)O_(6)` has `= 6 xx 0.35`
`= 2.1 xx 6.023 xx 10^(23) = 1.26 xx 10^(24)` carbon atoms.