Calculate normality of mixture obtained by mixing : 100 mL of 0.1 N `H_2SO_4 + 50` mL of 0.25 N NaOH.

Options

A. 0.167
B. 0.0167
C. 0.17
D. 0.067

Answer

B

Explanation

Meq. of `H_2SO_4 = 100 xx 0.1 = 10`
Meq. of NaOH = `50 xx 0.25 = 12.5`

`H_2SO_4` and NaOH neutralize each other.
Meq. of NaOH left `= 12.5 – 10 = 2.5`
Volume of new solution `= 100 + 50 = 150` mL
Normality of NaOH left = `2.5/150 = 0.0167`