Home
Class 9
CHEMISTRY
A constant current of 1.25 amperes is p...

A constant current of 1.25 amperes is passed through an electrolytic cell containing a 0.05 M solution of `CuSO_(4)` and a copper anode and a platinum cathode until 1.58 g of copper is deposited .
How long does the current flow to obtain 1.58 g of copper ?

Text Solution

Verified by Experts

Calculate the elctrochemical equivalent of copper and use the formula
`W=ZxxIxxt`
3841 . 9 seconds
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    CENGAGE CHEMISTRY|Exercise OLYMPIAD AND NTSE LEVEL EXERCISES |10 Videos
  • ELECTROCHEMISTRY

    CENGAGE CHEMISTRY|Exercise MULTIPLE CHOICE QUESTIONS WITH ONE OR MORE THAN ONE CORRECT ANSWER |20 Videos
  • CHEMICAL REACTIONS

    CENGAGE CHEMISTRY|Exercise OLYMPIAD AND NTSE LEVEL EXCERCISES|10 Videos
  • EQUIVALENT MASS

    CENGAGE CHEMISTRY|Exercise OLYMPIAD AND NTSE LEVEL EXERCISES|10 Videos

Similar Questions

Explore conceptually related problems

A current of 1.50 A was passed through an electrolytic cell containing AgNO_3 solution with inert electrodes. The weight of silver deposited was 1.50g . How long did the current flow ? (Molar mass of Ag=108 g " mol "^(-1), 1F=96500C " mol" ^(-1) ).

An electrolytic cell contains a solution of Ag_(2)SO_(4) and have platinum electrodes. A current is passed until 1.6gm of O_(2) has been liberated at anode. The amount of silver deposited at cathode would be