In photoelectric effect the slope of straight line graph between stopping potential `(V_(s))` and frequency of incident light (v) gives

Options

A. `10^(-14)`
B. `5xx10^(-14)`
C. `4xx10^(-15)`
D. `4xx10^(-34)`

Answer

C

Explanation

When light waves of differing frequencies are made inciden on the same surface the stopping potential `(V_(s))` differ as is evidenced from Einstein.s photoelectric equation given by
`hv-hv_(0)=eV_(s)`
where h is Planck.s constnat v, `v_(0)` the frequencies and e the charge

Hence `V(s)=(hv)/e=(hv_(0))/e`..i
comparing eq (i) with straight line equation
`y=mx+c`
slope `m=h/e`
Where `h=6.6xx10^(-34)Js,e=1.6`
`xx10^(-19)C`
`:.m=(6.6xx10^(-34))/(1.6xx10^(-19))=4.125xx10^(-15)`