A conducting wire of length L is bent in the form of an equilateral triangle. If current I is made to pass through it, then calculate the magnetic field intensity at the centre of the triangle.

Options

A. `2sqrt(3)(mu_(0)I)/(4piL)`
B. `(mu_(0)I)/(4piL)`
C. `sqrt(3)(mu_(0)I)/(4piL)`
D. zero

Answer

D

Explanation

B at O: (i) due to `I_(AB)` is `B_(AB)=K . 1/3 o.`
(ii) due toi `I_(BC)` is `B_(BC)=K1/3 o.`
(iii) due to `I_(AC)` is `B_(AC)=Kxx(2I)/3 ox`
net B at `O=K I/3+KI/3-K(2I)/3=0`
Here K is any constant.