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In a factory three types of toothbrushes...

In a factory three types of toothbrushes are manufactured everyday. On a certain day, the production is 570. The production of toothbrushes of second kind exceeds the production of toothbrushes of first kind by 100. Also, the total production of toothbrushes of first and second kinf is four times the production of third kind.

If x, y and z denotes the production of toothbrushes of three kinds, respectively then using matrix method, the algebraic representing of the given condition is :

A

`[[1,1,1],[1,1,0],[1,1,4]][[x],[y],[z]] = [[570],[100],[0]]`

B

`[[1,1,1],[1,-1,0],[1,1,4]] [[x],[y],[z]] = [[570],[100],[0]]`

C

`[[1,1,1],[1,-1,0],[1,1,-4]] [[x],[y],[z]] = [[570],[100],[0]]`

D

`[[1,1,1],[1,-1,0],[1,1,-4]] [[x],[y],[z]] = [[570],[-100],[0]]`

Text Solution

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The correct Answer is:
D
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