The vapour pressure of pure Benzene at a certain temperature is 0.850 bar. A non-volatile non-electrolyte solid weighing 0.5 g.when added to 39.0 g of benzene (molar mass 78 g `'mol"^(-1)`) vapour pressure is 0.845 bar. What is the molar mass of the solid substance ?

The vapour pressure of pure benzene at a certain temperature is 0.850 bar. A non-volatile, non-electrolyte solid weighing 0.5g when added to 39.0 g of benzene (molar mass 78 g "mol"^(-1) ), vapour pressure of the solution, then, is 0.845 bar. What is the molar mass of the solid substance ?

The vapour pressure of a solution having 2.0g of a solute X (molar mass 32 g mol^(-1)) in 100g of CS_(2) (vapour pressure 854 Torr) is 848.9 Torr. The molecular formula of the solute is

At 298 K, the vapour pressure of a solution of 7.5 g of non-volatile solute in 90 g of water is 2.8 kPa. If 18 g of water is added to this solution vapour pressure becomes solution the vapour pressure becomes 2.81 kPa at same temperature, the molar mass of solute in g mol^(-1) is

34.5 mL of phosphorus vapour weights 0.0625g at 546^@C and 0.1 bar pressure . What is the molar mass of phosphorus?

6 g of a non volatil, non electrolyte X dissolved in 100g of water freezes at -0.93^@C . The molar mass of X in g mol^(-1) is (K_f of H_2O=1.86kgmol^(-1)) .

When 25 g of a non-volatile solute is dissolved in 100g of water, the vapour pressure is lowered by 2.25 xx 10^(-1)mm . If the vapour pressure of water at 20^(@)C is mm, what is the molecular weight of the solute?

Vapour pressure of pure water at 27^@C is 3000k Pa. By dissolving 5 g of a non volatile molecular solid in 100 g of water the vapour pressure is decreased to 2985 k Pa. What si the molecular weight of solute?