Calculate the mass of a non-volatile solute (molar mass `40"g mol"^(-1)`) which should be dissolved in 114g Octane to reduce its vapour pressure to `80%`.

What weigth of a non-volatile solute (molar mass 40 g) should be dissolved in 114 g of octance to reduce its vapour pressure by 20%.

The weight in grams of a non-volatile solute (mol.wt.60) to be dissolved in 90g of water to produce a relative lowering of vapour pressure of 0.02 is

The weight in grams of a non-volatile solute (mol.wt.60) to be dissolved in 90 g of water to produce a relative lowering of vapour pressure of 0.02 is

1.0 g of a non-electrolyte solute (molar mass 250 g "mol"^(-1) ) was dissolved in 51.2 g of benzene. If the freezing point depression constant of benzene is 5.12 K kg "mol"^(-1) , the lowering in freezing point will be

100g of liquid A(molar mass 140"g mol"^(-1) ) was dissolved in 1000g of liquid B(molar mass 180"g mol"^(-1) ). The vapour pressure of pure liquid B was found to be 500 torr. Calculate the vapour pressure of pure liquid A and its vapour pressure in the solution if the total vapour pressure of the solution is 475 torr.

At 20^@C , the vapour pressure of diethyl ether is 442mm. When 6.4g. of a non-volatile solute is dissolved in 50g. of ether, the vapour pressure falls to 410mm. The Molecular weight of the solute is

What happens to the vapour pressure of a liquid when a non-volatile solute is dissolved in it ?

Calculate the vapour pressure , if 0.083 mole of a non-volatile solute is present in 80 g of ethanol at 25^@C , Vapour pressure of ethanol is 22.45 mm.

6 g of urea is dissolved in 90g of boiling water. The vapour pressure of the solution is