Which of the following options containing formula, bonding and nature of aqeous solution respectively is correct for the compound formed by two elements A and B having atomic numbers 1 and 17 , respectively?

Options

A. AB, Ionic, Acidic
B. `AB_(2)`, Ionic, Basic
C. AB, Covalent Acidic
D. `AB_(2)`, Covalent, Neutral

Explanation

To solve the question, we need to determine the formula, bonding type, and nature of the aqueous solution for the compound formed by elements A and B, which have atomic numbers 1 and 17, respectively.

### Step-by-Step Solution:

1. **Identify the Elements**:
- The element with atomic number 1 is Hydrogen (H).
- The element with atomic number 17 is Chlorine (Cl).

2. **Determine the Valence Electrons**:
- Hydrogen has 1 valence electron.
- Chlorine has 7 valence electrons.

3. **Bond Formation**:
- Hydrogen needs to gain 1 electron to complete its duplet (since it can only hold 2 electrons).
- Chlorine needs to gain 1 electron to complete its octet (it needs 8 electrons).
- Therefore, Hydrogen will donate its 1 electron to Chlorine, resulting in the formation of a bond.

4. **Write the Chemical Formula**:
- The resulting compound from this electron transfer is HCl (Hydrochloric Acid).

5. **Determine the Type of Bonding**:
- The electronegativity difference between Hydrogen and Chlorine is less than 1.7, indicating that the bond is covalent.
- Thus, HCl is a covalent compound.

6. **Nature of Aqueous Solution**:
- HCl, when dissolved in water, forms hydrochloric acid, which is known to be acidic in nature.

### Final Answer:
The correct options containing the formula, bonding type, and nature of the aqueous solution for the compound formed by elements A and B (H and Cl) are:
- Formula: HCl
- Bonding: Covalent
- Nature of Aqueous Solution: Acidic