A man of 60kg mass is in a lift. Find the apparent weight of the man when the lift is moving up with uniform speed(`g=10ms^(-2))`

Answer

To solve the problem of finding the apparent weight of a man in a lift moving upward with uniform speed, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Concept of Apparent Weight**:
- Apparent weight is the weight that a person feels when they are in an accelerating frame of reference, such as a lift. It can be calculated using the formula:
\[ W' = m(g + a) \]
- Where:
- \( W' \) = apparent weight
- \( m \) = mass of the person
- \( g \) = acceleration due to gravity
- \( a \) = acceleration of the lift

2. **Identify Given Values**:
- Mass of the man, \( m = 60 \, \text{kg} \)
- Acceleration due to gravity, \( g = 10 \, \text{m/s}^2 \)
- Since the lift is moving upward with uniform speed, the acceleration \( a = 0 \, \text{m/s}^2 \).

3. **Substitute Values into the Apparent Weight Formula**:
- Since the lift is moving at a uniform speed, we substitute \( a = 0 \) into the formula:
\[ W' = m(g + 0) \]
- This simplifies to:
\[ W' = mg \]

4. **Calculate the Apparent Weight**:
- Now substitute the values of \( m \) and \( g \):
\[ W' = 60 \, \text{kg} \times 10 \, \text{m/s}^2 \]
- Performing the multiplication:
\[ W' = 600 \, \text{N} \]

5. **Conclusion**:
- The apparent weight of the man when the lift is moving up with uniform speed is **600 Newtons**.