Home
Class 12
PHYSICS
A rock is 1.5 xx 10^(9) years old. The r...

A rock is `1.5 xx 10^(9)` years old. The rock contains `.^(238)U` which disintegretes to form `.^(236)U`. Assume that there was no `.^(206)Pb` in the rock initially and it is the only stable product fromed by the decay. Calculate the ratio of number of nuclei of `.^(238)U` to that of `.^(206)Pb` in the rock. Half-life of `.^(238)U` is `4.5 xx 10^(9). years. `(2^(1/3) = 1.259)` .

A

1

B

2

C

4

D

5

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • NUCLEAR PHYSICS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE PRACTICE SHEET (ADVANCED) More than one correct answer Type Questions|5 Videos

  • NUCLEAR PHYSICS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE PRACTICE SHEET (ADVANCED) Linked Comprehension Type Questions Passage-I :|2 Videos

  • NUCLEAR PHYSICS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE LEVEL-II (LECTURE SHEET (ADVANCED)) Integer Type Questions )|3 Videos

  • MOVING CHARGES AND MAGNETISM

    AAKASH SERIES|Exercise EXERCISE-III|49 Videos

  • NUCLEI

    AAKASH SERIES|Exercise Practice Exercise|40 Videos

Similar Questions

Explore conceptually related problems

In a smaple of rock, the ration .^(206)Pb to .^(238)U nulei is found to be 0.5. The age of the rock is (given half-life of U^(238) is 4.5 xx 10^(9) years).

A radioactive sample of ^(238)U decay to Pb through a process for which the half is 4.5 xx 10^(9) year. Find the ratio of number of nuclei of Pb to ^(238)U after a time of 1.5 xx 10^(9) year Given (2)^(1//3)= 1.26

A sample of uranium mineral was found to contain Pb^(208) and U^(238) in the ratio of 0.008 : 1. Estimate the age of the mineral (half life of U^(238) is 4.51 xx 10^(9) years).

In an ore containing Uranium, the ratio of U^(238) to Pb^(206 nuceli is 3 . Calculate the age of the ore, assuming that alll the lead present in the ore is the final stable, product of U^(238) . Take the half-like of U^(238) to be 4.5 xx 10^(9) years. In (4//3) = 0.288 .

The final product of U^(238) is Pb^(206) . A sample of pitchblende contains 0.0453 g of Pb^(206) for every gram of U^(238) present in it. Supposing that the mineral pitchblende formed at the time of formation of the earth did not contain any Pb^(206) , calculate the age of the earth (half-life period of U^(238) = 4.5 xx 10^(9) years).

In an ore containing uranium, the ratio of ^238U to 206Pb nuclei is 3. Calculate the age of the ore, assuming that all the lead present in the ore is the final stable product of ^238U . Take the half-life of ^238U to be 4.5xx10^9 years.

Two radioactive materials X_(1) and X_(2) have decay constants 10 lamda and lamda respectively. If initially they have the same number of nuclei, if the ratio of the number of nuclei of X_(1) to that of X_(2) will be 1//e after a time n/(9lamda) . Find the value of n ?

.^(238)U decays with a half-life of 4.5 xx10^(9) years, the decay series eventually ending at .^(206)Pb , which is stable. A rock sample analysis shows that the ratio of the number of atoms of .^(206)Pb to .^(238)U is 0.0058. Assuming that all the .^(206)Pb is produced by the decay of .^(238)U and that all other half-lives on the chain are negligible, the age of the rock sample is (ln 1.0058 =5.78 xx10^(-3)) .

A sample of U^(238) ("half life" = 4.5 xx 10^(9)yr) ore is found to contain 23.8 g" of " U^(238) and 20.6g of Pb^(206) . Calculate the age of the ore

U^(238) is found to be in secular equilibrium with Ra^(226) on its ore. If chemical analysis shows 1 nuclei of Ra^(226) per 3.6xx10^(-6) nuclei of U^(238) , find the half-life of U^(238) . Given the half-life is 1500 years.