For an eletromagnetic wave, the magnetic field is given by the folloeing equation:
`vecB=1.6 xx 10^(-6)cos (2 xx 10^7Z+6 xx 10^(15)t)(2hati=hatj)Wb m^(-2)`
Electric field is equal to

Options

A. &\vec{E}=4.8\times 10^{2}\cos\left(2\times 10^{7}z+6\times 10^{15} t\right+(\hat{i}-2 \hat {j}) \frac {V} {m} $`
B. `vecE=4.8 xx 10^2 cos (2 xx 10^(7)z-6 xx 10^(15)t)(-2 hati+hatj)V/m`
C. $\vec {E}=4.8 \times 10^ {2} \cos \left(2 \times 10^ {7} z+6 \times 10^ {15} t\right)(-\hat {i}+2 \hat {}) \frac {V} {m}$
D. $\vec {E}=4.8 \times 10^{2} \cos \left(2 \times 10^{7} 2-6 \times 10^ {15} t\right)(2 \hat {i}+\hat {j}) \frac {V} {m}$

Answer

A

Explanation

$\vec {E} \times \vec {B}=\vec {V}$