The gravitational force between earth of radius R and mass M and rod of length R and mass m placed as shown in the figure is 12GMm. Find the value of n.

Answer

`24.00`

Explanation

Net force on the rod is equal to centripetal force.
`f_g=(GMm)/((R+x)^2)R)dx`

`=(GMm)/R oversetr underset(0) int (dx)/((R+x)^2)`
`f_g=(GMm)/(2R^2)`