A rock is launched upward at `45^(@)`. A bee moves along the trajectory of the rock at a constant speed equal to the initial speed of the rock. What is the magnitude of acceleration (in `m//s^(2)`) of the bee at the top point of the trajectory? For the rock, neglect the air resistance.

Answer

`000198.60`

Explanation

For stone, at the highest point Radius of curvature,
R= `(u//sqrt(2))^2/g=u^2/(2g)`
The bee follows the stone.s trajectory with the constant speed u
`a=u^2/R=u^2/(u^2//2g)=2g`
`a=2g=19.6 m s^(_1)`