The force acting on a pilot of mass 75 kg at the highest point of a vertical circular loop of radius 0.350 km, when he completes it with a steady speed of 355 km `hr^-1` is `P/100` Newtons. Then, the value of `P/100` is: (Take g`=10 m s^(-2))`

Answer

`13.34`

Explanation

The resultant force with which the pilot is pressed into seat at highest point,
`F=(mv^2)/r-mg`
`75/350((355 xx 10^3)/3600)-75 xx 10`

`3/14 (1775/18)^2-750`
`=2083.75-750`
`=1333.75 N`