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The diameter of a flywheel is increased ...

The diameter of a flywheel is increased by 1% keeping the mass same. Increase in its moment of inertia about the central axis is

A

0.02

B

0.04

C

0.01

D

0.005

Text Solution

Verified by Experts

The correct Answer is:
A
The moment of inertia of a fly whel is given by:
`I=MR^(2)`
`(dI)/I=2(dR)/Rimplies100xx(dI)/I`
`=2[(dR)/Rxx100]`
`:.` % increase in moment of inertia
`=2xx1=`
`2%`
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