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An ideal gas with pressure P, volume V and temperature T is expanded isothermally to a volume 2V and final pressure `P_(I)`. The same gas is expanded adiabatically to a volume 2V and final pressure in this case is `P_(A)`. In terms of the ratio of the two specific heats for the gas `gamma`, the ratio `P_(I)//P_(A)` is

A

`2^(gamma-1)`

B

`2^(1-gamma)`

C

`2^(gamma)`

D

`2^(gamma)`

Text Solution

Verified by Experts

The correct Answer is:
A

For a isothermal process,
PV=constant
`:.PV=P_(1)2V`
`P_(1)=P/2`…….i
For an adiabatic process
`PV_(gamma)=` cosntant
`:.PV^(gamma)=P_(A)(2V)^(gamma)`
or `P_(A)=P/(2^(gamma))`……….ii
Divide I by ii we get
`(P_(1))/(P_(2))=(2^(gamma))/2=2^(gamma-1)`
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