Home
Class 12
PHYSICS
The dimension of impulse is [M^(2b)L^(3a...

The dimension of impulse is `[M^(2b)L^(3a)T^(4c)]`.Find the value of `3a+2b-4c`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of \(3a + 2b - 4c\) given the dimension of impulse as \([M^{2b}L^{3a}T^{4c}]\). ### Step 1: Understand the definition of impulse Impulse is defined as the product of force and time. Mathematically, it can be expressed as: \[ \text{Impulse} = \text{Force} \times \text{Time} \] ### Step 2: Find the dimension of force The dimension of force can be derived from Newton's second law, which states that force is mass times acceleration: \[ \text{Force} = \text{Mass} \times \text{Acceleration} \] The dimension of mass is \([M]\) and the dimension of acceleration is \([L T^{-2}]\). Therefore, the dimension of force is: \[ \text{Dimension of Force} = [M][L T^{-2}] = [M^1 L^1 T^{-2}] \] ### Step 3: Find the dimension of impulse Since impulse is force multiplied by time, we can write: \[ \text{Impulse} = \text{Force} \times \text{Time} \] The dimension of time is \([T]\). Thus, the dimension of impulse becomes: \[ \text{Dimension of Impulse} = [M^1 L^1 T^{-2}] \times [T^1] = [M^1 L^1 T^{-1}] \] ### Step 4: Set up the equation with given dimensions We are given that the dimension of impulse is \([M^{2b}L^{3a}T^{4c}]\). Therefore, we can equate the dimensions: \[ [M^1 L^1 T^{-1}] = [M^{2b} L^{3a} T^{4c}] \] ### Step 5: Compare the powers of M, L, and T From the equation above, we can compare the powers of \(M\), \(L\), and \(T\): 1. For \(M\): \[ 2b = 1 \quad \Rightarrow \quad b = \frac{1}{2} \] 2. For \(L\): \[ 3a = 1 \quad \Rightarrow \quad a = \frac{1}{3} \] 3. For \(T\): \[ 4c = -1 \quad \Rightarrow \quad c = -\frac{1}{4} \] ### Step 6: Calculate \(3a + 2b - 4c\) Now we can substitute the values of \(a\), \(b\), and \(c\) into the expression \(3a + 2b - 4c\): \[ 3a + 2b - 4c = 3\left(\frac{1}{3}\right) + 2\left(\frac{1}{2}\right) - 4\left(-\frac{1}{4}\right) \] Calculating each term: - \(3a = 3 \times \frac{1}{3} = 1\) - \(2b = 2 \times \frac{1}{2} = 1\) - \(-4c = -4 \times -\frac{1}{4} = 1\) Adding these together: \[ 3a + 2b - 4c = 1 + 1 + 1 = 3 \] ### Final Answer Thus, the value of \(3a + 2b - 4c\) is: \[ \boxed{3} \]

To solve the problem, we need to find the value of \(3a + 2b - 4c\) given the dimension of impulse as \([M^{2b}L^{3a}T^{4c}]\). ### Step 1: Understand the definition of impulse Impulse is defined as the product of force and time. Mathematically, it can be expressed as: \[ \text{Impulse} = \text{Force} \times \text{Time} \] ...
Promotional Banner

Topper's Solved these Questions

  • NTA TPC JEE MAIN TEST 53

    NTA MOCK TESTS|Exercise PHYSICS |30 Videos
  • NTA TPC JEE MAIN TEST 55

    NTA MOCK TESTS|Exercise PHYSICS (SUBJECTIVE NUMERICAL)|10 Videos

Similar Questions

Explore conceptually related problems

If the dimensions of B^(2)l^(2)C are [M^(a)L^(b)T^(c)] , then the value of a+b+c is [Here B,l and C represent the magnitude of magnetic field, length and capacitance respectively]

If a,b,c are distinct positive prime integers such that a^(2)b^(3)c^(4)=49392, find the value of a,b and c

If a=4, b=-3, c=2 , find the value of 4a^(2)+5b-12c ..

If a + b + c = 0 and a^(2) + b^(2) + c^(3) = 4, them find the value of a^(4) + b^(4) +c^(4) .

If a^(2) + b^(2) + c^(2) = 2(a-b-c)-3 , then the value of 4a - 3b + 5c is

Suppose A=B^(n)C^(m) , where A has dimensions LT, B has dimensions L^(2)T^(-1) , and C has dimensions LT^(2) , Then the exponents n and m have the values: (A) 2//3,1//3 " " (B) 2,3 " " (C) 4//5,-1//5 " " (D) 1//5,3//5 (E) 1//2,1//2

If a+2b+3c=4, then find the least value of a^(2)+b^(2)+c^(2)

Dimension of sqrt((in_(0))/(mu_(0))) are (A) [M L^(2) T^(-3) A^(-2)] (B) [M^(-1) L^(-2) T^(3) A^(2)] (C) [M^(2)L^(2)T^(-3) A^(2)] (D) [M^(-1) L^(2) T^(3) A^(2)]

NTA MOCK TESTS-NTA TPC JEE MAIN TEST 54-PHYSICS
  1. Figure shows a small loop carrying a current I. The curved portion is ...

    Text Solution

    |

  2. On heating water, bubbles beings formed at the bottom of the vessel de...

    Text Solution

    |

  3. The power of spectacles lens required for a person is -5 dioptre when ...

    Text Solution

    |

  4. Image is formed for the shortsighted person

    Text Solution

    |

  5. The diameter of a flywheel is increased by 1% keeping the mass same. I...

    Text Solution

    |

  6. A solid sphere slides down a smooth inclined plane of inclination thet...

    Text Solution

    |

  7. An ideal gas with pressure P, volume V and temperature T is expanded i...

    Text Solution

    |

  8. The phase difference between current and voltage in an AC circuit is (...

    Text Solution

    |

  9. A liquid of density rho is filled in two indentical cylindrical vessel...

    Text Solution

    |

  10. An engine pumps up 100 kg of water through a height of 10m in 5s. Give...

    Text Solution

    |

  11. When a charged particle is accelerated through 1.5volts its de -Brogli...

    Text Solution

    |

  12. The intensity fo a light pulse traveling along a communication channel...

    Text Solution

    |

  13. On mole of hydrogen gas in its molecular form is heated from temperatu...

    Text Solution

    |

  14. As shown in the figure two infinitely long, identical wires are bent b...

    Text Solution

    |

  15. A source that is 0.10 m away from a fresnel biprism of angle 2^(@) whi...

    Text Solution

    |

  16. A disc of radius R=10cm, oscillations as a physical pendulum. The pend...

    Text Solution

    |

  17. The dimension of impulse is [M^(2b)L^(3a)T^(4c)].Find the value of 3a+...

    Text Solution

    |

  18. A soap bubble is formed from 10^(-3)g of soap solution. When it is fil...

    Text Solution

    |

  19. How much time (in minutes) will a liquid take to cool from 46^(@)C to ...

    Text Solution

    |

  20. A diatomic gas undergoes same change of temperature by two different p...

    Text Solution

    |