A diatomic gas undergoes same change of temperature by two different processes (i) at constant volume and (ii) at constant pressure. The heat supplied in the two cases will be in the ratio of

Answer

`01.40`

Explanation

To raise the temperature of a gas, the amount of heat that must be supplied
At constant pressure `Q_(p)=mC_(p)DeltaT`
At constant voume `Q_(v)=mC_(v)DeltaT`
`:.(Q_(p))/(Q_(r))=(C_(p))/(C_(r))`
For diatomic gas
`(C_(p))/(C_(v))=7/5=1.4`
`:.(Q_(p))/(Q_(v))=1.4`