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The area of a square and a rectangle are...

The area of a square and a rectangle are equal. If side of the square is 50 cm and breadth of the rectangle is 30 cm. Find :
(i) Length of the rectangle.
(ii) Perimeter of the rectangle.

A

(i)- 80 cm, (ii) 225 cm

B

(i) - 83.3 cm, (ii) - 226.6 cm

C

(i) 89.2 cm, (ii) - 226.6 cm

D

(i)-75.5 cm, (ii) 225.5 cm

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Calculate the area of the square. The area of a square is given by the formula: \[ \text{Area} = \text{side} \times \text{side} \] Given that the side of the square is 50 cm: \[ \text{Area of square} = 50 \, \text{cm} \times 50 \, \text{cm} = 2500 \, \text{cm}^2 \] ### Step 2: Set the area of the rectangle equal to the area of the square. Since the area of the rectangle is equal to the area of the square: \[ \text{Area of rectangle} = \text{Area of square} = 2500 \, \text{cm}^2 \] ### Step 3: Use the area of the rectangle to find the length. The area of a rectangle is given by the formula: \[ \text{Area} = \text{length} \times \text{breadth} \] We know the breadth of the rectangle is 30 cm. Let \( L \) be the length of the rectangle. Therefore: \[ L \times 30 \, \text{cm} = 2500 \, \text{cm}^2 \] To find \( L \), we rearrange the equation: \[ L = \frac{2500 \, \text{cm}^2}{30 \, \text{cm}} \] Calculating this gives: \[ L = \frac{2500}{30} \approx 83.33 \, \text{cm} \] ### Step 4: Calculate the perimeter of the rectangle. The perimeter \( P \) of a rectangle is given by the formula: \[ P = 2 \times (L + B) \] Substituting the values of \( L \) and \( B \): \[ P = 2 \times (83.33 \, \text{cm} + 30 \, \text{cm}) \] Calculating this gives: \[ P = 2 \times 113.33 \, \text{cm} \approx 226.66 \, \text{cm} \] ### Final Answers: (i) Length of the rectangle: \( \approx 83.33 \, \text{cm} \) (ii) Perimeter of the rectangle: \( \approx 226.66 \, \text{cm} \) ---
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