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Which of the following options is CORREC...

Which of the following options is CORRECT ?

A

Additive identity if a rational number a is `-1//a`

B

For rational numbers a,b and c `a-(b-c) = (a-b)-c`

C

The value of `1/(1+(2/3)/(1+2/3+(8/9)/(1-2/3))) " is " 13/15`

D

Reciprocal of `1/x` , (where `x != 0 `) is -x .

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze each of the given options and determine which one is correct. Let's break it down step by step. ### Step 1: Analyze the First Option The first option states that the additive inverse of \( A \) is \( -\frac{1}{A} \). **Explanation**: The additive inverse of a number \( A \) is the number that, when added to \( A \), results in zero. The correct additive inverse of \( A \) is \( -A \), not \( -\frac{1}{A} \). **Conclusion**: The first option is incorrect. ### Step 2: Analyze the Second Option The second option involves the expression \( A - (B - C) \). **Explanation**: When we simplify \( A - (B - C) \), we distribute the negative sign: \[ A - (B - C) = A - B + C \] The expression on the right side is \( A - B - C \). **Conclusion**: Since \( A - B + C \) is not equal to \( A - B - C \), the second option is also incorrect. ### Step 3: Analyze the Fourth Option The fourth option states that the reciprocal of \( \frac{1}{X} \) is \( -X \). **Explanation**: The reciprocal of \( \frac{1}{X} \) is \( X \), not \( -X \). **Conclusion**: The fourth option is incorrect. ### Step 4: Analyze the Third Option The third option involves the expression: \[ \frac{1}{1 + \frac{2}{3}} \div \left(1 + \frac{2}{3} + \frac{8}{9}\right) \div \left(1 - \frac{2}{3}\right) \] **Step 4.1: Simplify the Denominator** First, simplify \( 1 - \frac{2}{3} \): \[ 1 - \frac{2}{3} = \frac{1}{3} \] **Step 4.2: Simplify the Expression** Now, we need to simplify the entire expression: \[ \frac{1}{1 + \frac{2}{3}} \div \left(1 + \frac{2}{3} + \frac{8}{9}\right) \] **Step 4.3: Simplify \( 1 + \frac{2}{3} \)** \[ 1 + \frac{2}{3} = \frac{3}{3} + \frac{2}{3} = \frac{5}{3} \] **Step 4.4: Simplify \( 1 + \frac{2}{3} + \frac{8}{9} \)** Convert \( 1 \) to a fraction with a common denominator: \[ 1 = \frac{9}{9} \quad \text{so,} \quad 1 + \frac{2}{3} + \frac{8}{9} = \frac{9}{9} + \frac{6}{9} + \frac{8}{9} = \frac{23}{9} \] **Step 4.5: Substitute Back** Now we substitute back into the expression: \[ \frac{1}{\frac{5}{3}} \div \frac{23}{9} \div \frac{1}{3} \] **Step 4.6: Simplify Further** The expression simplifies to: \[ \frac{3}{5} \div \frac{23}{9} \div \frac{1}{3} \] **Step 4.7: Final Calculation** Calculating \( \frac{3}{5} \div \frac{23}{9} \) gives us: \[ \frac{3}{5} \times \frac{9}{23} = \frac{27}{115} \] Now, dividing by \( \frac{1}{3} \): \[ \frac{27}{115} \times 3 = \frac{81}{115} \] ### Conclusion After analyzing all options, the only correct option is the third one. ### Final Answer The correct option is the third one.
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