Home
Class 8
MATHS
A farmer has a field in the shape of an ...

A farmer has a field in the shape of an isosceles trapezium whose perimeter is 215 m. One of its non parallel sides is 50m. What is the sum of its parallel sides?

A

115m

B

60m

C

165m

D

135m

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we can follow these instructions: ### Step 1: Understand the shape and given information We have an isosceles trapezium, which means it has two parallel sides and two non-parallel sides that are equal in length. The perimeter of the trapezium is given as 215 m, and one of the non-parallel sides is 50 m. **Hint:** Remember that in an isosceles trapezium, the non-parallel sides are equal. ### Step 2: Define the sides of the trapezium Let's denote: - The lengths of the two parallel sides as \( a \) and \( b \). - The lengths of the two non-parallel sides (which are equal) as \( c \). From the problem, we know: - \( c = 50 \) m (the length of one non-parallel side). - The perimeter \( P = a + b + c + c = 215 \) m. **Hint:** The perimeter of a shape is the sum of the lengths of all its sides. ### Step 3: Write the equation for the perimeter Substituting the known values into the perimeter equation: \[ P = a + b + 2c \] \[ 215 = a + b + 2(50) \] **Hint:** Substitute the value of \( c \) into the equation. ### Step 4: Simplify the equation Now, simplify the equation: \[ 215 = a + b + 100 \] Subtract 100 from both sides: \[ a + b = 215 - 100 \] \[ a + b = 115 \] **Hint:** Make sure to perform the arithmetic correctly when simplifying. ### Step 5: Conclusion The sum of the lengths of the two parallel sides \( a \) and \( b \) is 115 m. **Final Answer:** The sum of the parallel sides is **115 m**.
Promotional Banner

Topper's Solved these Questions

  • IMO QUESTION PAPER 2018-19 SET -B

    SCIENCE OLYMPIAD FOUNDATION |Exercise ACHIEVERS SECTION|5 Videos
  • IMO QUESTION PAPER 2018-19 SET -B

    SCIENCE OLYMPIAD FOUNDATION |Exercise ACHIEVERS SECTION|5 Videos
  • IMO QUESTION PAPER 2017-18 SET-B

    SCIENCE OLYMPIAD FOUNDATION |Exercise ACHIEVERS SECTION|5 Videos
  • IMO QUESTION PAPER 2018-19 SET- A

    SCIENCE OLYMPIAD FOUNDATION |Exercise Achievers Section|5 Videos

Similar Questions

Explore conceptually related problems

The area of a field in the shape of a trapezium measures 1440 m2. The perpendicular distance between its parallel sides is 24 m. If the ratio of the parallel sides is 5 : 3, the length of the longer parallel side is (a) 45 m (b) 60 m (c) 75 m (d) 120 m

The area of a field in the shape of trapezium measures 1440 m^(2) . The perpendicular distance between its parallel sides is 24 m. If the ratio of the parallel sides is 5 : 3, the length of the longer parallel side is :

The area of a trapezium is 180cm^(2) and its height is 12cm. If one of the parallel sides is double that of the other,find the two parallel sides.

The area of an isosceles trapezium is 176 cm^(2) and the height is (2)/(11) of the sum of its parallel sides. If the ratio of the length of the parallel sides be 4 : 7 , then the length of a diagonal is :

The area of the trapezium is 105cm^(2) and its height is 7cm. If one of the parallel sides is longer than the by 6cm find the two parallel sides.

The area of a trapezium shaped field is 480m2, the distance between two parallel sides is 15m and one of the parallel side is 20m. Find the other parallel side.

A farmer's land is in the shape of a trapezium which has its parallel sides measuring 2.56 yards and 3.44 yeards and the distance between the parallel sides in 1.44 yards. The cost of ploughing the land is Rs. 1800 per square yard. What amount will (in Rs.) have to be spent in order to plough the entire land ?