Home
Class 11
PHYSICS
A rough vertical board has an accelerati...


A rough vertical board has an acceleration `a` so that a 2 kg block pressing against it dows not fall. The coefficient of friction between the block and the board should be

A

`gt` g/a

B

`lt` g/a

C

`=g//a`

D

`gt` a/g

Text Solution

Verified by Experts

The correct Answer is:
A
`f gt mg implies mu ma gt mg`
`implies mu gt g//a`
Promotional Banner

Topper's Solved these Questions

  • FRICTION

    ERRORLESS|Exercise NCERT BASED QUESTIONS (Kinetic Friction )|20 Videos

  • FRICTION

    ERRORLESS|Exercise NCERT BASED QUESTIONS (Motion on Inclined Surface )|11 Videos

  • FLUID MECHANICS

    ERRORLESS|Exercise ASSERTION AND REASON|23 Videos

  • GRAVITATION

    ERRORLESS|Exercise Assertion and Reason |25 Videos

Similar Questions

Explore conceptually related problems

A horizontal force of 10N is necessary to just hold a block stationary against as well. The coefficient of friction between the block and the wall is 0.2. The weight of the block is

A block of mass M is held against a rough vertical wall by pressing it with a finger . If the coefficient of friction between the block and the wall is mu and the acceleration due to gravity is g , calculate the minimum force required to be applied by the finger to hold the block against the wall.

A board is moving with velocity v on a smoother horizontal plane. The upper surface of the board is rough on which a ball falls with velocity v and rebounds with velocity (v)/(2) . The mass of the board is same as that of ball. After the collision, the board comes to state of rest. The co-efficient of friction between the board and the ball is

In the given system, a block of mass m is resting on a board which makes an angle theta with the horizontal. What should be the minimum value of theta , so that the block just starts moving downwards? The coefficient of friction between the surfaces of the board and the block is mu .