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A particle of mass m is moving in a circ...

A particle of mass m is moving in a circular orbit of radius r in a force field given by `vec(F)=-(K)/(r^(2))hat(r)` . The angular momentum L of the particle about the centre varies as

A

`L prop sqrtr`

B

`L prop r^(3//2)`

C

`L prop (1)/(sqrtr)`

D

`L prop r^(1//3)`

Text Solution

Verified by Experts

The correct Answer is:
A

`(mv^(2))/(r)= (K)/(r^(2)) rArr v= sqrt((K)/(mr))`
`L= mvr = sqrt(mrK)` Thus we get `L prop sqrtr`
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