if the earth is treated as a sphere of radius Radn mass M, Its angular momentum about the axis of its rotation with period T, is

Options

A. `(piMR^(3))/(T)`
B. `(MR^(2)pi)/(T)`
C. `(2piMR^(2))/(5T)`
D. `(4piMR^(2))/(5T)`

Answer

D

Explanation

`L=Iomega=(2)/(5)MR^(2)xx(2pi)/(T)=(4piMR^(2))/(5T)`