Home
Class 11
CHEMISTRY
The modern atomic weight scale is based ...

The modern atomic weight scale is based on

A

`C^(12)`

B

`O^(16)`

C

`H^(1)`

D

`C^(13)`

Text Solution

Verified by Experts

The correct Answer is:
A
Factual
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS OF CHEMISTRY

    ERRORLESS|Exercise NCERT BASED QUESTIONS( THE MOLE CONCEPT)|38 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    ERRORLESS|Exercise NCERT BASED QUESTIONS( PERCENTAGE COMPOSITION & MOLECULAR FORMULA)|9 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    ERRORLESS|Exercise NCERT BASED QUESTIONS(LAWS OF CHEMICAL COMBINATION )|13 Videos

  • REDOX REACTIONS

    ERRORLESS|Exercise ASSERTION & REASON|6 Videos

  • STATES OF MATTER

    ERRORLESS|Exercise ASSERTION AND REASON|11 Videos

Similar Questions

Explore conceptually related problems

The number of atomic weight scale is based on:

The modern atomic mass unit if based on the mass of ………

The modern periodic table is based on

The fundamental property on which the modern periodic table is based is atomic number, not atomic mass.

Modern periodic table is based on

How it can be proved that the basic structure of the Modern Periodic Table is based on the electronic configurationof atoms of different elements?

Knowledge Check

  • The modern atomic mass scale is based on :-

    A
    `C^(12)`
    B
    `o^(16)`
    C
    `H^(1)`
    D
    `C^(13)`

  • The number of atomic weight scale is based on:

    A
    `C^(12)`
    B
    `O^(16)`
    C
    `H^(1)`
    D
    `C^(13)`

  • The modern basis of atomic weight is

    A
    Isotope `H^(1) = 1.000`
    B
    Oxygen `= 16.000`
    C
    Isotope `O^(16) = 16.000`
    D
    Isotope `C^(12) = 12.000`
    • ERRORLESS-SOME BASIC CONCEPTS OF CHEMISTRY-NCERT BASED QUESTIONS(ATOMIC, MOLECULAR AND EQUIVALENT MASSES)
    1. The modern atomic weight scale is based on

      Text Solution

      |

    2. 1 mol of CH(4) contains

      Text Solution

      |

    3. Boron has two stable isotopes, ""^(10)B(19%) and ""^(11)B(81%). The at...

      Text Solution

      |

    4. The percentage of element M is 53 in its oxide of molecular formula M(...

      Text Solution

      |

    5. The atomic weights of two alements A and B are 40 and 80 reapectively....

      Text Solution

      |

    6. If N(A) is Avogadro's number then number of valence electrons in 4.2 g...

      Text Solution

      |

    7. Arrange the following in the order of increasing mass (at. Mass of O=1...

      Text Solution

      |

    8. 1 amu is

      Text Solution

      |

    9. On reduction with hydrogen, 3.6 g of an oxide of matel left 3.2 g of m...

      Text Solution

      |

    10. Caffeine has a molecular weight of 194. If it contains 28.9 % by mass ...

      Text Solution

      |

    11. The element whose one atom has mass of 10.86xx10^(-26) kg is (Atomic ...

      Text Solution

      |

    12. Vapour density of a metal chloride is 66. Its oxide contains 53% metal...

      Text Solution

      |

    13. 1.5g CdCl(2) was formed to contain 0.9g Cd. Calculate MO, the atomic w...

      Text Solution

      |

    14. What is the volutme of CO(2) liberted in litres at 1 atmosphere and 0^...

      Text Solution

      |

    15. Approximate atomic weight of an element is 26.89. If its equivalent we...

      Text Solution

      |

    16. Dulong and Petit's law is valid only for

      Text Solution

      |

    17. A metal M of equivalent mass E forms an oxide of molecular formula M(x...

      Text Solution

      |

    18. If the molecular weight of H(3)PO(3) is M, its equivalent weight will ...

      Text Solution

      |

    19. What is the concentration of nitrate ions if equal volumes of 0.1 M Ag...

      Text Solution

      |

    20. The mass of a molecule of water is

      Text Solution

      |