Arrange the following in the order of increasing mass (at. Mass of O=16, Cu=63, N=14)
(I) one atom of oxygen (II) one atom of nitrogen
(III) `1xx10^(-10)` mole of oxygen (IV) `1xx10^(-10)` mole of copper

Options

A. `I lt II lt III lt IV`
B. `I lt II lt III lt IV`
C. `III lt II lt IV lt I`
D. `IV lt II lt III lt I`

Answer

A

Explanation

Mass of one atom of oxygen ` = (16)/(6.022 xx 10^(23)) = 2.66 xx 10^(-23)`
Mass of one atom of nitrogen
` = (14)/(6.022 xx 10^(23)) = 2.23 xx 10^(-23)`
Mass of `1 xx 10^(-10) ` mole of oxgyen ` = 32 xx 10^(-10)`
Mas of `1 xx 10^(-10) ` mole of copper `= 63 xx 1 xx 10^(-10)`
`=63 xx 10^(-10)`
So, the order of increasing mass is `II lt I lt III lt IV`