Which amount of dioxygen (in grams) contains `1.8 xx 10^(22)` molecules ?

Options

A. 9.6
B. 0.096
C. 96
D. 0.96

Answer

D

Explanation

Molecular weight of `O_(2)` (dioxygen) is 32g
32g = 1 mole ` = 6.023 xx 10^(23)` molecules of `O_(2)` contains 32g of `O_(2)`
` therefore 1.8 xx 10^(23)` molecules of `O_(2)` contains amount of
`O_(2)` in gram ` = (32 xx 1.8 xx 10^(22))/(6.023 xx 10^(23)) = 0.956 ~= 0.96`