In a mole of water vapours at STP, the volume actually occupied or taken by the molecules (i.e., Avogadro's No.`xx` volume of one molecule) is

Options

A. Zero
B. Less than 1% of 22.4 litres
C. About 10% of the volume of container
D. 1% to 2% of 22.4 litres

Answer

B

Explanation

1 mole of water ` = 18 g = 18 cm^(3)`
Volume of 1 mole of water vapour at S.T.P.
` = 22.4L = 22400 cm^(3)`
Percentage volume actually occupied by water molecules ` = (18)/(22400) xx 100 lt 0.1`
Percentage volume actually occupied by water molecules ` = (18)/(22400) xx 100 lt 0.1`