Complete combustion of 0.858 g of compound X gives 2.63 g of `CO_(2)` and 1.28 g of` H_(2)`O. The lowest molecular mass X can have

Options

A. 75
B. 93.5
C. 100
D. 80

Answer

A

Explanation

`% C = (12)/(44) xx (W_(co_(2))/(W)) xx 100 = (12)/(44) xx (2.63)/(0.858) xx 100 = 83.6%`
`%H = (2)/(18) xx (W_(H_(2)O))/(W) xx 100 = (2)/(18) xx (1.28)/(858) xx 100 = 16.4%`