0.75 g platinic chloride, a monoacid base on ignition gave 0.245 g playinum. The molecular weight of the base is

Options

A. 75
B. 93.5
C. 100
D. 80

Answer

B

Explanation

`("Wt.of" B_(2)H_(2)PtCl_(6))/(2B + 410) = ("Wt.of Pt")/(195)`
`therefore (0.75)/(2B + 410) = (0.245)/(195) rArr B = 93.5`
Eq. wt. of base = 93.5, since it is monoacidic
`therefore ` Mol.wt of base ` = 93.5 xx 1 = 93.5`