A gaseous mixture contain `CH_(4)` and `C_(2)H_(6)` in equimolecular proportion. The weight of 2.24 litres of this mixture at NTP is

Options

A. 4.6 g
B. 1.6 g
C. 2.3 g
D. 23 g

Answer

C

Explanation

Equimolecular proportion means both gases occupied equal volume ` = (2.24)/(2) = 1.12 L`
For `CH_(4)` :
`22.4L CH_(4)` has mass = 16 g
`1.12 L CH_(4)` has mass ` = (16)/(22.4) xx 1.12 = 0.8 g`
For `C_(2)H_(6)`
`22.4L C_(2)H_(6)` has mass = 30g
`1.12 L C_(2)H_(6)` has mass `= (30)/(22.4) xx 1.12 = (3.0)/(2)g = 1.5g`
Total mass ` = 1.5g + 0.8 g = 2.3g`