What is the volume of water consumed during acid hydrolysis of 1.368 kg of surose ?

Options

A. `0.072 dm^(3)`
B. `0.720 dm^(3)`
C. `0.18 dm^(3)`
D. `0.018 dm^(3)`

Answer

A

Explanation

`C_(12)H_(22)O_(11) + H_(2)O overset(H^(+)) to underset("D.Glucose")(C_(6)H_(12)O_(6)) + underset("D.Fructose")(C_(6)H_(12)O_(6))`
342 g of sucrose consumed `18 cm^(3)` volume of water .
Hence 1368 g sucrose consumed volume of waer is ` = (18 cm^(3) xx 1368)/(342 g) = 72 cm^(3) ~= 0.072 dm^(3)`
`(1 m^(3) = 10^(3) dm^(3) = 10^(6) cm^(3))`