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M is molecular weight of KMnO(4). The eq...

M is molecular weight of `KMnO_(4)`. The equivalent weight of `KMnO_(4)` when it is converted into `K_(2)MnO_(4)` is

A

M

B

`M//3`

C

`M//5`

D

`M//7`

Text Solution

Verified by Experts

The correct Answer is:
A
`KMoverset(+7)(nO_(4))to K_(2)overset(+6)(MnO_(4))`
Change in 0.5 per atom = 7-6=1
`KMnO_(4) = ("Molecular weight of" KMnO_(4))/("Change of 0.5 per atom") = (M)/(1) = M`
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