`1.520 g` of the hydroxide of a metal on ignition gave `0.995 g` of oxide. The equivalent weight of metal is

Options

A. 1.52
B. 0.995
C. 19
D. 9

Answer

D

Explanation

`("Wt.of metal hydroxide")/("Wt. of metal oxide") = (EM + EOH^(-))/(EM + EO^(-))`
`therefore (1.520)/(0.995) = (x + 17)/(x+8) therefore 1.520x + 1.520 xx 8`
` = 0.995x + 0.995 xx 17`
`1.520x + 12.160 = 0.995x + 16.195`
` or 0.525x = 4.755`
`x = (4.755)/(0.525) = 9`