4 g of copper was dissolved in concentrated nitric acid. The copper nitrate solutio on strong heating gave 5g of its oxide. The equivalent weight of copper is

Options

A. 23
B. 32
C. 12
D. 20

Answer

B

Explanation

In 5 g CuO, 4 g Cu and 1 g O be present.

Empirical formula = CuO of oxide
In this oxide, oxidation no. of Cu = + 2
Equivalent weight ` = ("Molecular weight")/("Oxidation no.") = (63.5)/(2) ~~ 31.75` but Equivalent weight should be an integral no. = 32.