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In a mixture, two enantiomers are found ...

In a mixture, two enantiomers are found to be present in 85% and 15% respectively. The enatiomeric excess (e,e) is

A

0.85

B

0.15

C

0.7

D

0.6

Text Solution

Verified by Experts

The correct Answer is:
C
15% will form racemic mixture with another 15% so, excess is (85 – 15) =70%.
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